使用xlm在Python中解析xml（一种正确的方法）

Question

我使用Python中的requests模块得到了一个响应，响应是xml形式的。我想解析它并从每个'dt'标记中获取详细信息。我不能用lxml来实现。在

以下是xml响应：

<?xml version="1.0" encoding="utf-8" ?>
    <entry_list version="1.0">
        <entry id="harsh">
            <ew>harsh</ew><subj>MD-2</subj><hw>harsh</hw>
            <sound><wav>harsh001.wav</wav><wpr>!h@rsh</wpr></sound>
            <pr>ˈhärsh</pr>
            <fl>adjective</fl>
            <et>Middle English <it>harsk,</it> of Scandinavian origin; akin to Norwegian <it>harsk</it> harsh</et>
            <def>
                <date>14th century</date>
                <sn>1</sn>
                <dt>:having a coarse uneven surface that is rough or unpleasant to the touch</dt>
                <sn>2 a</sn>
                <dt>:causing a disagreeable or painful sensory reaction :<sx>irritating</sx></dt>
                <sn>b</sn>
                <dt>:physically discomforting :<sx>painful</sx></dt>
                <sn>3</sn>
                <dt>:unduly exacting :<sx>severe</sx></dt>
                <sn>4</sn>
                <dt>:lacking in aesthetic appeal or refinement :<sx>crude</sx></dt>
               <ss>rough</ss>
           </def>
           <uro><ure>harsh*ly</ure> <fl>adverb</fl></uro>
           <uro><ure>harsh*ness</ure> <fl>noun</fl></uro>
       </entry>
    </entry_list>

Answer 1

from xml.dom import minidom

# List with dt values
dt_elems = []

# Process xml getting elements by tag name 
xmldoc = minidom.parse('text.xml')
itemlist = xmldoc.getElementsByTagName('dt')

# Get the values
for i in itemlist:
    dt_elems.append(" ".join(t.nodeValue for t in i.childNodes if t.nodeType==t.TEXT_NODE))

# Print the list result
print dt_elems  

Answer 2

一种简单的方法是向下遍历xml文档的层次结构。在

import requests
from lxml import etree

re = requests.get(url)
root = etree.fromstring(re.content)
print(root.xpath('//entry_list/entry/def/dt/text()'))

这将为xml文档中的每个“dt”标记提供文本值。在