我用Python构建了一个用于预订剧院座位的代码。代码运行良好,除了我需要能够重复代码在一个循环,所以一旦一些座位被预订,你可以选择预订更多的座位。在
代码如下:
NumSeat = input ("Please enter the number of seats you desire: ")
print (" ")
import re
if re.match("[0-9]", NumSeat):
if int(NumSeat) > 6:
print ("You may only book a maximum of 6 seats")
else:
if int(NumSeat) < 1:
print ("You must book at least 1 seat")
else:
SeatRow = input ("Please enter the row you want to sit in: ")
if len(SeatRow) > 1:
print ("Invalid row")
else:
if SeatRow.count ("A") or SeatRow.count ("a") == 1:
print ("The seats avaiable in row", SeatRow, "for", int(NumSeat), "people are", RowA[0],"-", RowA[int(NumSeat)-1])
RowA = RowA[int(NumSeat):]
else:
if SeatRow.count ("B") or SeatRow.count ("b") == 1:
print ("The seats avaiable in row", SeatRow, "for", int(NumSeat), "people are", RowB[0],"-", RowB[int(NumSeat)-1])
RowB = RowB[int(NumSeat):]
else:
if SeatRow.count ("C") or SeatRow.count ("c") == 1:
print ("The seats avaiable in row", SeatRow, "for", int(NumSeat), "people are", RowC[0],"-", RowC[int(NumSeat)-1])
RowC = RowC[int(NumSeat):]
else:
if SeatRow.count ("D") or SeatRow.count ("d") == 1:
print ("The seats avaiable in row", SeatRow, "for", int(NumSeat), "people are", RowD[0],"-", RowD[int(NumSeat)-1])
RowD = RowD[int(NumSeat):]
else:
if SeatRow.count ("E") or SeatRow.count ("e") == 1:
print ("The seats avaiable in row", SeatRow, "for", int(NumSeat), "people are", RowE[0],"-", RowE[int(NumSeat)-1])
RowE = RowE[int(NumSeat):]
else:
print("Invalid row")
else:
print ("You must input a number")
如果你有什么建议就太好了
但你的问题是为了避免重复,你可以创建一本字典。通过使用以row为键的字典,并在其中添加座位数组,可以完全删除if/else或if-elif。例如,您可能需要强制行成为第一个元素
a1
,否则将需要进行一些解析。例如,您可以:相关问题 更多 >
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