尝试从字符串转换为in时，以10为基数的int（）的文本无效

Question

我对编程相当陌生，我一直在用python编写projecteuler问题。I've been trying to do question 8并遇到上述错误。我不太清楚这意味着什么，也不知道如何解决它。我的代码是：

class question8(object):
"""This question gives a 1000 digit number and asks you to find the largest product of 13 consecutive digits"""
def __init__(self):
       self.inputSequence = "7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450"

def productFinder(self):
       input = []
       num = '1'
       for i in range(0,1001):
           input.append(int(self.inputSequence[i:i+1]))


       largestProduct = 0
       largestPosition = 0
       product = 1;
       x=0
       y=0
       while x<len(input):
          y=x
          for i in range(0,14):
              product = product*input[x]
              x+=1
          if product>largestProduct:
              largestProduct=product
              x = y
              x+=1
          else: 
              x+=1
       return largestProduct

错误来自线路”输入.附加（内景(自输入序列[i:i+1]）“。提前感谢您的帮助！在

Answer 1

您应该避免使用input之类的内置函数作为变量名

通过将这一行分解成组件，可以更好地调试这一行

   for i in range(0,1001):
       s = self.inputSequence[i:i+1]
       print(repr(s))
       input.append(int(s))

甚至是

^{pr2}$

最好是完全避免在一个范围内循环

inp = [int(s) for s in self.inputSequence]

Answer 2

考虑一下您的代码：

def productFinder(self):
       input = []
       num = '1'
       for i in range(0,1001):
           input.append(int(self.inputSequence[i:i+1]))

当它到达字符串末尾时：

^{pr2}$

1000位数字

0到999是一千步

0到1000等于一千零一

0到1001是一千零二

我想你把电话号码的最后一个空出来了。在