带套接字的kivyTextInput

Question

我尝试创建一个Python服务器（使用python3）从客户机（用Kivy开发）接收信息。我试图使用套接字，但出现错误： “文本输入'不支持缓冲区接口” 如果您能告诉我我的错误在哪里，我将不胜感激：）

我的委托人：

from kivy.app import App
#kivy.require("1.8.0")
from kivy.uix.label import Label
from kivy.uix.gridlayout import GridLayout
from kivy.uix.textinput import TextInput
import socket


class LoginScreen(GridLayout):
    def __init__(self,**kwargs):
        super(LoginScreen, self).__init__(**kwargs)
        self.cols=2
        my_socket = socket.socket()
        host=socket.gethostname()
        my_socket.connect((host,80))

        self.add_widget(Label(text='username'))
        self.username = TextInput(multiline=False)
        self.add_widget(self.username)
        my_socket.send(self.username)
        my_socket.close()

        self.add_widget(Label(text='Password'))
        self.password = TextInput(multiline=False,password=True)
        self.add_widget(self.password)


class SimpleKivy(App):
    def build(self):
        return LoginScreen()


if __name__=='__main__':
    SimpleKivy().run()

我的服务器：

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感谢您的帮助：）

Answer 1

我的客户代码：

from kivy.app import App
# kivy.require("1.8.0")
from kivy.uix.label import Label
from kivy.uix.gridlayout import GridLayout
from kivy.uix.textinput import TextInput
from kivy.uix.button import Button
import socket


class LoginScreen(GridLayout):
    def __init__(self, **kwargs):
        super(LoginScreen, self).__init__(**kwargs)
        self.cols = 3
        self.my_socket = socket.socket()
        #host = socket.gethostname()
        #port = 8585
        self.my_socket.connect(('127.0.0.1', 8080))

        self.add_widget(Label(text='username'))
        self.username = TextInput(multiline=False)
        self.add_widget(self.username)

        self.add_widget(Label(text='Password'))
        self.password = TextInput(multiline=False, password=True)
        self.add_widget(self.password)

        self.submit_button = Button(text='Submit')
        self.submit_button.bind(on_press=self.submit_username)
        self.add_widget(self.submit_button)

    def submit_username(self, *args):
        # Make sure to validate the input before submitting to the server
        self.my_socket.send(self.username.text.encode('utf-8'))


class SimpleKivy(App):
    def build(self):
        return LoginScreen()

这是我的服务器代码：

^{pr2}$

也许我需要写：self.my_插座.close（）在客户端代码中？在

Answer 2

针对缓冲区的问题，需要将bytes()发送到套接字。它不接受字符串。 我认为使用套接字是如此低的水平，不是这里的最佳实践。尝试开发一个restapi，它接受来自客户端的请求并为您执行db操作。CherryPy非常小，对于这样一个简单的开始是很好的。回到客户端代码，尝试创建一个Button，并将其绑定到一个方法，该方法将用户名发送到服务器。在当前代码中，您正在将kivy.uix.textinput.TextInput对象发送到服务器，而您需要使用对象的text属性发送它的文本。我建议做如下修改

from kivy.app import App
# kivy.require("1.8.0")
from kivy.uix.label import Label
from kivy.uix.gridlayout import GridLayout
from kivy.uix.textinput import TextInput
from kivy.uix.button import Button
import socket


class LoginScreen(GridLayout):
    def __init__(self, **kwargs):
        super(LoginScreen, self).__init__(**kwargs)
        self.cols = 3
        self.my_socket = socket.socket()
        host = socket.gethostname()
        port = 8585
        self.my_socket.connect((host, port))

        self.add_widget(Label(text='username'))
        self.username = TextInput(multiline=False)
        self.add_widget(self.username)

        self.add_widget(Label(text='Password'))
        self.password = TextInput(multiline=False, password=True)
        self.add_widget(self.password)

        self.submit_button = Button(text='Submit')
        self.submit_button.bind(on_press=self.submit_username)
        self.add_widget(self.submit_button)

    def submit_username(self, *args):
        # Make sure to validate the input before submitting to the server
        self.my_socket.send(bytes(self.username.text))


class SimpleKivy(App):
    def build(self):
        return LoginScreen()


if __name__ == '__main__':
    SimpleKivy().run()