我是python新手,我试图将抓取数据转换为CSV文件,但没有成功。在
代码如下:
from urllib.request import urlopen, Request
from bs4 import BeautifulSoup
import os
import random
import re
from itertools import cycle
def cleanhtml(raw_html):
cleanr = re.compile('<.*?>') #cleaning the strings from these terms
cleantext = re.sub(cleanr, '', raw_html)
return cleantext
def scrape(url, filename, number_id):
"""
This function scrapes a web page looking for text inside its html structure and saves it in .txt file.
So it works only for static content, if you need text in a dynamic part of the web page (e.g. a banner)
look at the other file. Pay attention that the retrieved text must be filtered out
in order to keep only the part you need.
url: url to scrape
filename: name of file where to store text
number_id: itis appended to the filename, to distinguish different filenames
"""
#here there is a list of possible user agents
user_agent = random.choice(user_agent_list)
req = Request(url, headers={'User-Agent': user_agent})
page = urlopen(req).read()
# parse the html using beautiful soup and store in variable 'soup'
soup = BeautifulSoup(page, "html.parser")
row = soup.find_all(class_="row")
for element in row:
viaggio = element.find_all(class_="nowrap")
Partenza = viaggio[0]
Ritorno = viaggio[1]
Viaggiatori = viaggio[2]
Costo = viaggio[3]
Title = element.find(class_="taglist bold")
Content = element.find("p")
Destination = Title.text
Review = Content.text
Departure = Partenza.text
Arrival = Ritorno.text
Travellers = Viaggiatori.text
Cost = Costo.text
TuristiPerCasoList = [Destination, Review, Departure, Arrival, Travellers, Cost]
print(TuristiPerCasoList)
在这里,一切正常。现在我要把它变成一个CSV文件。 我试过这样:
^{pr2}$但它不会返回CSV文件中的任何内容。 有人能帮助我理解如何将其转换为CSV文件吗?在
在每次迭代中,都要重新分配
TuristiPerCasoList
值。实际需要的是
list
的list
,其中字符串是特定单元格的值,第二个列表包含一行的值,第一个列表包含所有行。在为此,您应该在主列表中附加一个表示行的列表:
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