<p>这对我来说是一个很好的进入python的任务,它已经被搁置了一段时间。我在此展示我的第一个python脚本:</p>
<pre><code>import sys, re
with open( sys.argv[1] , 'r' ) as f:
css = f.read()
# remove comments - this will break a lot of hacks :-P
css = re.sub( r'\s*/\*\s*\*/', "$$HACK1$$", css ) # preserve IE<6 comment hack
css = re.sub( r'/\*[\s\S]*?\*/', "", css )
css = css.replace( "$$HACK1$$", '/**/' ) # preserve IE<6 comment hack
# url() doesn't need quotes
css = re.sub( r'url\((["\'])([^)]*)\1\)', r'url(\2)', css )
# spaces may be safely collapsed as generated content will collapse them anyway
css = re.sub( r'\s+', ' ', css )
# shorten collapsable colors: #aabbcc to #abc
css = re.sub( r'#([0-9a-f])\1([0-9a-f])\2([0-9a-f])\3(\s|;)', r'#\1\2\3\4', css )
# fragment values can loose zeros
css = re.sub( r':\s*0(\.\d+([cm]m|e[mx]|in|p[ctx]))\s*;', r':\1;', css )
for rule in re.findall( r'([^{]+){([^}]*)}', css ):
# we don't need spaces around operators
selectors = [re.sub( r'(?<=[\[\(>+=])\s+|\s+(?=[=~^$*|>+\]\)])', r'', selector.strip() ) for selector in rule[0].split( ',' )]
# order is important, but we still want to discard repetitions
properties = {}
porder = []
for prop in re.findall( '(.*?):(.*?)(;|$)', rule[1] ):
key = prop[0].strip().lower()
if key not in porder: porder.append( key )
properties[ key ] = prop[1].strip()
# output rule if it contains any declarations
if properties:
print "%s{%s}" % ( ','.join( selectors ), ''.join(['%s:%s;' % (key, properties[key]) for key in porder])[:-1] )
</code></pre>
<p>我相信这是可行的,并且在最近的Safari、Opera和Firefox上输出它的测试结果很好。它将打破除下划线之外的CSS黑客攻击&;/**/hacks!如果你有很多黑客的话,不要使用小型化程序(或者把它们放在一个单独的文件中)。</p>
<p>关于我的Python的任何提示都很感激。不过,请温柔一点,这是我第一次。:-)</p>