特金特：根。后(), root.after\u取消()

Question

我有一个秒表，我想在计数达到0后复位。不过，我在使用“取消后”功能时遇到问题。有人能帮忙吗？
结果是它一直在继续，我想终止“after”函数。在

def countdown(self):
    if self.totalseconds == 1:
        self.master.after_cancel(self.after_id)
    self.totalseconds = self.totalseconds - 1
    stdtime = self.total_seconds_to_standard(self.totalseconds)
    self.time.set(stdtime)
    self.after_id = self.master.after(1000,self.countdown)

Answer 1

明白了。。。福巴。在

def countdown(self):
    self.totalseconds = self.totalseconds - 1
    stdtime = self.total_seconds_to_standard(self.totalseconds)
    self.time.set(stdtime)
    self.after_id = self.master.after(1000,self.countdown)
    if self.totalseconds == 0:
        self.master.after_cancel(self.after_id)