擅长:python、mysql、java
<p>更新您的代码以在<code>identifier</code>为无效类型时引发错误,所有这些都将变得清晰:</p>
<pre><code>def approveCam(room, identifier):
if not room.bpass:
return
if type(identifier) in [str, unicode, int]:
user = room._getUser(identifier)
if not user:
return "User " + str(identifier) + " was not found..."
else:
raise ValueError('Invalid type for identifier')
if user.broadcasting:
return
room._sendCommand("privmsg", [room._encodeMessage("/allowbroadcast " + room.bpass),
"#0,en" + "n" + str(user.id) + "-" + user.nick])
</code></pre>