我想按一下下面的“学习”键,按一下“代码”键。如你所见,它从“A”开始。。。然后通过显式地将其改为“B”来作弊。我想访问StringVar中的第一个位置(可能是索引0),然后根据其ascii代码将其作为字符递增,然后将其转换回StringVar。这可能吗?这里有比使用StringVar更简单的方法吗?在
from Tkinter import *
from tkMessageBox import *
print "this is a test"
class Demo(Frame):
def __init__(self):
self.createGUI()
print "init"
#self.__mainWindow = Tk()
def destroy(self):
print "destroy"
def createGUI(self):
Frame.__init__(self)
self.pack(expand = YES, fill = BOTH)
self.master.title("Demo")
self.trackLabel = StringVar()
self.trackLabel.set("A")
self.trackDisplay = Label(self, font = "Courier 14", textvariable = self.trackLabel, bg = "black", fg = "green")
self.trackDisplay.grid(sticky = W+E+N+S)
self.button1 = Button(self, text = "Move Forward", width = 20, command = self.bpress)
self.button1.grid(row = 2, column = 0, sticky = W+E+N+S)
self.bind_all('<Key>', self.print_contents)
def bpress(self):
self.trackLabel.set("B") # I want to do this so it cycles through the alphabet!
print "ow"
#INSTEAD I WANT TO MAKE TRACKLABEL ASCII CHAR + 1 HERE
def print_contents(self, event):
print "testing here...", self.trackLabel.get()
#INSTEAD I WANT THIS TO MAKE TRACKLABEL ASCII CHAR + 1 HERE BY KEY, OR ABOVE BY BUTTON PRESS
# run the program
def main():
tts = Demo()
tts.mainloop()
if __name__ == "__main__":
main()
您可以使用
ord
获得字符的ascii代码,并使用chr
将代码转换回字符。在相关问题 更多 >
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