变量数据类型错误?

2024-06-25 23:16:53 发布

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我有一个类,打算从Git获取用户名和他的电子邮件提交:

class BitbucketData(object):

    def get_user_name(self):

        proc = subprocess.Popen("git --no-pager show -s --format='%an'", stdout=subprocess.PIPE)
        committer_name = proc.stdout.read()

        if committer_name:
            return committer_name

    def get_user_email(self):

        proc = subprocess.Popen("git --no-pager show -s --format='%aE'", stdout=subprocess.PIPE)
        committer_email = proc.stdout.read()

        if committer_email:
            return committer_email

然后它用于向用户发送通知(底部是工作版本-不带变量-所有senderreceiver数据集显式设置,而不是变量中的数据-他们在这里评论):

^{pr2}$

问题是-如果我使用来自变量的数据(例如to_address = 'user@domain.com'或使用BitbucketData()类与to_address = repo.get_user_email()一起使用-我从Office365服务器收到一个错误:

...
reply: '250 2.1.0 Sender OK\r\n'
reply: retcode (250); Msg: 2.1.0 Sender OK
send: "rcpt TO:<'user@domain.com'>\r\n"
reply: '501 5.1.3 Invalid address\r\n'
reply: retcode (501); Msg: 5.1.3 Invalid address
...
  File "C:\Python27\lib\smtplib.py", line 742, in sendmail
    raise SMTPRecipientsRefused(senderrs)
smtplib.SMTPRecipientsRefused: {"'user@domain.com'\n": (501, '5.1.3 Invalid address')}

使用变量时,代码如下所示:

class Services(object):


    def sendmail(self, event):

        repo = BitbucketData()

        to_address = repo.get_user_email()
        #to_address = 'user@domain.com'
        to_name = repo.get_user_name()
        #to_name = 'Test user'
        from_address = 'user@domain.com'

        subject = 'Bamboo build and deploy ready'
        sender = 'Bamboo agent <user@domain.com>'

        text_subtype = 'plain'
        message = """
        Hello, {}.

        Your build ready.
        Link to scenario: URL
        Link to build and deploy results: {})

        """.format(to_name, os.environ['bamboo_resultsUrl'])

        msg = MIMEText(message, text_subtype)
        msg['Subject'] = subject
        msg['From'] = sender
        msg['To'] = to_name

        smtpconnect = smtplib.SMTP('outlook.office365.com', 587)
        smtpconnect.set_debuglevel(1)
        smtpconnect.starttls()
        smtpconnect.login('user@domain.com', 'password')
        smtpconnect.sendmail(from_address, to_address, msg.as_string())
        smtpconnect.quit()

        print('Mail sent')

        print(repo.get_user_email())

我(或Microsoft SMTP…)在这里做错了什么?在

UPD公司

def sendmail(self, event):

    repo = BitbucketData()
    print(repr(repo.get_user_email()))
    ...

给我:

...
Creating new AutoEnv config
"'user@domain.com'\n"
send: 'ehlo pc-user.kyiv.domain.net\r\n'
...

Tags: tonameselfcomgetaddressemaildomain
1条回答
网友
1楼 · 发布于 2024-06-25 23:16:53

似乎您正在从git命令接收以下输出-

"'user@domain.com'\n"

您将直接将其传递给smtpconnect,这是导致问题的原因,因为这不是有效的电子邮件地址。你可能需要从中得到实际的字符串。获得它的一种方法是使用^{}函数。示例-

^{pr2}$

get_user_email()函数返回电子邮件时,需要执行此操作。很可能committer_name也有这个问题,所以您可能也需要这样做。在


来自ast.literal_eval()-

ast.literal_eval(node_or_string)

Safely evaluate an expression node or a Unicode or Latin-1 encoded string containing a Python literal or container display. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.

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