我编写了这段python代码,试图将对象转换为一个由1和0组成的字符串,但是解码失败了,因为数据无法解压。代码如下:
def encode(obj):
'convert an object to ones and zeros'
def tobin(str):
rstr = ''
for f in str:
if f == "0": rstr += "0000"
elif f == "1": rstr += "0001"
elif f == "2": rstr += "0010"
elif f == "3": rstr += "0100"
elif f == "4": rstr += "1000"
elif f == "5": rstr += "1001"
elif f == "6": rstr += "1010"
elif f == "7": rstr += "1100"
elif f == "8": rstr += "1101"
elif f == "9": rstr += "1110"
else: rstr += f
return rstr
import pickle, StringIO
f = StringIO.StringIO()
pickle.dump(obj, f)
data = f.getvalue()
import base64
return tobin(base64.b16encode(base64.b16encode(data)))
def decode(data):
def unbin(data):
rstr = ''
for f in data:
if f == "0000": rstr += "0"
elif f == "0001": rstr += "1"
elif f == "0010": rstr += "2"
elif f == "0100": rstr += "3"
elif f == "1000": rstr += "4"
elif f == "1001": rstr += "5"
elif f == "1010": rstr += "6"
elif f == "1100": rstr += "7"
elif f == "1101": rstr += "8"
elif f == "1110": rstr += "9"
return rstr
import base64
ndata = base64.b16decode(base64.b16decode(unbin(data)))
import pickle, StringIO
f = StringIO.StringIO(ndata)
obj = pickle.load(f)
return obj
我想我有更好的解决办法。这应该更安全,因为它“加密”了所有东西,而不仅仅是数字:
我认为有几个问题,但一个是当你解码时,你需要在unbin()函数中迭代4个字符组,而不是像你现在这样的单个字符。在
您的
bin
和unbin
函数并不是相反的,因为bin
有一个else子句,它只将字符逐字放入输出中,而unbin
没有else子句来传递它们。在相关问题 更多 >
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