擅长:python、mysql、java
<p>将dict项传递给该函数时使用**</p>
<pre><code>**{
'multiplicand1': 3,
'multiplicand2': 4,
}
</code></pre>
<p><strong>输出:</strong></p>
^{pr2}$
<p>正如@svk在评论中指出的,<code>functionWrapper</code>的doctstring说:</p>
<blockquote>
<p>This function requires as input a function and a dictionary of named
arguments for that function.</p>
</blockquote>
<p>因此,在这种情况下,您需要将函数定义更改为:</p>
<pre><code>def functionWrapper(function, kwargs):
</code></pre>
<p>同时也要纠正口述中的打字错误,否则答案为0:</p>
<pre><code>'multiplicand1': 3,
'multiplicand1': 4, #Change this to 'multiplicand2
</code></pre>
<p>'</p>