如何使用PySDL2将SDL_Surface传递到SDL_LockTexture？

Question

我正在尝试将SDL_表面成员传递给SDL_LockTexture：

texture = SDL_CreateTexture(renderer, SDL_PIXELFORMAT_ARGB8888, SDL_TEXTUREACCESS_STREAMING, width, height)
surface = SDL_CreateRGBSurface(0, width, height, 32, 0x00FF0000, 0x0000FF00, 0x000000FF, 0xFF000000)
SDL_LockTexture(texture, 0, ctypes.byref(surface.contents.pixels), ctypes.byref(surface.contents.pitch))

TypeError: byref() argument must be a ctypes instance, not 'int'

这里定义了SDL曲面：surface.py

^{pr2}$

这里定义了SDL\u LockTexture:render.py

SDL_LockTexture = _bind("SDL_LockTexture", [POINTER(SDL_Texture), POINTER(SDL_Rect), POINTER(c_void_p), POINTER(c_int)], c_int)

在调用SDL_CreateRGBSurface之后，调试器说曲面的像素和间距成员都是int类型的。我做错什么了？在

Answer 1

我也遇到了同样的问题，试图将像素传递到PyOpenGL函数中。由于某些原因，字段存储为int。您需要将其转换为void pointer。尝试：

SDL_LockTexture(texture, 0, ctypes.byref(ctypes.c_void_p(surface.contents.pixels)), ctypes.byref(ctypes.c_int(surface.contents.pitch))