创建一个2D python数组来存储d

Question

正在寻找在python中将此代码存储在2D数组中的方法。我试过做一个1D数组，然后把它变成2D数组，但是我的代码仍然很麻烦，不能工作。4和6之间的差距不是打字错误。任何帮助都将不胜感激。在

recno1inds11 = nonzero(data11[:,1]==no1)[0]
recno2inds11 = nonzero(data11[:,1]==no2)[0]
recno3inds11 = nonzero(data11[:,1]==no3)[0]
recno4inds11 = nonzero(data11[:,1]==no4)[0]

recno6inds11 = nonzero(data11[:,1]==no6)[0]
recno7inds11 = nonzero(data11[:,1]==no7)[0]
recno8inds11 = nonzero(data11[:,1]==no8)[0]
recno9inds11 = nonzero(data11[:,1]==no9)[0]
recno10inds11 = nonzero(data11[:,1]==no10)[0]
recno11inds11 = nonzero(data11[:,1]==no11)[0]
recno12inds11 = nonzero(data11[:,1]==no12)[0]
recno13inds11 = nonzero(data11[:,1]==no13)[0]
recno14inds11 = nonzero(data11[:,1]==no14)[0]
recno15inds11 = nonzero(data11[:,1]==no15)[0] 
recno16inds11 = nonzero(data11[:,1]==no16)[0]
recno17inds11 = nonzero(data11[:,1]==no17)[0]
recno18inds11 = nonzero(data11[:,1]==no18)[0]
recno19inds11 = nonzero(data11[:,1]==no19)[0]
recno20inds11 = nonzero(data11[:,1]==no20)[0]
recno21inds11 = nonzero(data11[:,1]==no21)[0] 
recno22inds11 = nonzero(data11[:,1]==no22)[0]
recno23inds11 = nonzero(data11[:,1]==no23)[0]
recno24inds11 = nonzero(data11[:,1]==no24)[0]
recno25inds11 = nonzero(data11[:,1]==no25)[0]
recno26inds11 = nonzero(data11[:,1]==no26)[0]
recno27inds11 = nonzero(data11[:,1]==no27)[0]
recno28inds11 = nonzero(data11[:,1]==no28)[0]
recno29inds11 = nonzero(data11[:,1]==no29)[0]
recno30inds11 = nonzero(data11[:,1]==no30)[0]

Answer 1

通常，你不想有30个这样的独立变量，你应该有一个由30个值组成的数组。在

如果有，这将是一行代码；您可能需要将右边的数组转置到第二个轴上，然后使用==运算符。在

>>> data11 = np.array([[1,2,3],[4,5,6],[7,8,9]])
>>> data11[:,1]
array([2, 5, 8])
>>> no1to5 = np.array([1, 2, 3, 4, 5])
>>> data11[:,1] == no1to5.reshape((5,1))
array([[False, False, False],
       [ True, False, False],
       [False, False, False],
       [False, False, False],
       [False,  True, False]], dtype=bool)

当然，您也可以应用nonzero，抓取第一个轴，…无论您想做什么，只要您首先有一个向量，就可以对它进行矢量化，而不是只与绑定它们的变量名中的元信息相关的大量单独值的集合。在