擅长:python、mysql、java
<p>在输入<code>while loop</code>之前,必须定义<code>Z</code>;否则,如果<code>S != 1</code>,则在尝试返回循环时,<code>Z</code>未定义:</p>
<pre><code>def HTR(S, T):
Z = None #< choose the value you wish to return is S != 1
while S == 1:
Z = 60 #< Z is set to 60
if (S == 2): #< S already equals 1 at this point
Z = 60 + (60*.5)
elif (S == 3): #< S already equals 1 at this point
Z = 60*2
else:
Z = 0 #< then Z is always set to zero
# this is probably not the behavior you are expecting!
return Z
</code></pre>