从大量1d列表创建2d列表python

Question

嗨，所有我有麻烦创建一个二维列表从许多1d列表。我的代码如下

  lis=[average, average1, average2, average3, average4, average5, average6, average7, average8, average9]
  totalaverage= 3


  print
  print "Station 1 = Station 0 from menu. Please read all other stations accordingly"
  print
  for i,x in enumerate(lis):
  if x < totalaverage:
    aboveaverage = " {} average is less than {}".format(i+1,totalaverage )


    option = 0
    comicdb = []

    record = {}
    record = aboveaverage
    comicdb.append(record)
    print comicdb


    elif x > totalaverage:
     belowaverage = "{} average is greater than {}".format(i+1,totalaverage)
     print belowaverage

当我打印comicdb时，我得到以下结果。在

^{pr2}$

我想知道的是。有没有可以添加的代码，这样我就可以将所有这些单列表合并成一个双列表，这样我的代码在打印时看起来像这样。在

[[' 1 average is less than 3'],
[' 2 average is less than 3'],
[' 3 average is less than 3'],
[' 4 average is less than 3'],
[' 5 average is less than 3'],
[' 6 average is less than 3'],
[' 7 average is less than 3'],
[' 8 average is less than 3'],
[' 9 average is less than 3'],
[' 10 average is less than 3']]

本质上，我希望所有这些单独的列表组合成一个双列表，这样我就可以使用双列表单独访问每个列表。我想在以后的代码中分别打印每个列表。在

Answer 1

在python中，可以将列表附加到列表中。在

new_list = []
for i,x in enumerate(lis):
if x < totalaverage:
    aboveaverage = " {} average is less than {}".format(i+1,totalaverage )
    option = 0
    comicdb = []
    record = {}
    record = aboveaverage
    comicdb.append(record)
    new_list.append(comicdb)
    print comicdb

    elif x > totalaverage:
        belowaverage = "{} average is greater than {}".format(i+1,totalaverage)
        print belowaverage
print new_list