tex中的多词协调

Question

我有一个words文件来查找它们在文本中的一致性（最多3个位置左右）

文件字数：

buy

time

glass

home

red

文本文件：

After almost a decade selling groceries online, Amazon has failed to make a major dent on its own as consumers have shown a stubborn urge to buy items like fruits, vegetables and meat in person. Do you find yourself spending more time on your phone than you ... mindlessly passing time on a regular basis by staring at your phone? The process can be fraught with anxiety, as many different glass styles are available, and points of view clash on what is proper and necessary

脚本：

def keywordsContext(file, fileName):
    #file: text file
    #fileName: words file

    with open(file, "r") as f, open(fileName, "r") as fi:

        corpus = f.read().split()
        pivot = fi.read().split()

        for keywords in pivot:
            if keywords in corpus:
                index = pivot.index(keywords)
                contexts = keywords+":", pivot[index-3:index], pivot[index+1:index+4]
                print(contexts)
            else:
                pass

输出：

('buy:', [], ['time', 'glass', 'home'])

('time:', [], ['glass', 'home', 'red'])

('glass:', [], ['home', 'red'])

None

我想要的输出：

^{4磅}$

编辑

还有。。。如果同一个词出现不止一次？我做了一个测试（在语料库中再放一句话来重复“玻璃”这个词）。我试着放一段时间（语料库）！=0，但它是一个循环，重复使用相同的输出。。。在

^{pr2}$

输出：

buy: stubborn urge to buy items like fruits,

time: yourself spending more time on your phone

glass: as many different glass styles are available,

buy: stubborn urge to buy items like fruits,

time: yourself spending more time on your phone

glass: as many different glass styles are available,

buy: stubborn urge to buy items like fruits,

time: yourself spending more time on your phone

glass: as many different glass styles are available,

...

Answer 1

def keywordsContext(file, fileName):

    with open(file, "r") as f, open(fileName, "r") as fi:

        corpus = f.read().split()
        pivot = fi.read().split()
        for keywords in pivot:
            if keywords in corpus:
                index = corpus.index(keywords)
                contexts = keywords+":", corpus[index-3:index+4]
                print(contexts)
            else:
                pass

输出

^{pr2}$

Answer 2

列表名称有一些错误。试试看：

def keywordsContext(file, fileName):
#file: text file
#fileName: words file

with open(file, "r") as f, open(fileName, "r") as fi:

    corpus = f.read().split()
    pivot = fi.read().split()
    for keywords in pivot:
        if keywords in corpus:
            lst_index = 0
            for i in range(0, corpus.count(keywords)):
                inde = corpus.index(keywords, lst_index)
                contexts = keywords+": "+ ' '.join(corpus[inde-3:inde+4])
                lst_index = inde+1
                print(contexts)
        else:
            pass

编辑：根据OP edit，此程序打印所有出现的word

Answer 3

def keywordsContext(file, fileName):
    #file: text file
    #fileName: words file
    with open(file, "r") as f, open(fileName, "r") as fi:

        corpus = f.read().split()
        pivot = fi.read().split()
        for keywords in pivot:
            if keywords in corpus:
                index = corpus.index(keywords)
                contexts = "'" + keywords + "' : " + " ".join(corpus[index - 3 : index + 4])
                print(contexts)
            else:
                pass

输出：

^{pr2}$