httplib.InvalidURL:非数字端口:

2024-10-02 22:27:08 发布

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我正在尝试执行一个脚本,该脚本检查是否存在多个URL:

import httplib

with open('urls.txt') as urls:
    for url in urls:
        connection = httplib.HTTPConnection(url)
        connection.request("GET")
        response = connection.getresponse()
        if response.status == 200:
            print '[{}]: '.format(url), "Up!"

但我犯了个错误:

Traceback (most recent call last):
  File "test.py", line 5, in <module>
    connection = httplib.HTTPConnection(url)
  File "/usr/lib/python2.7/httplib.py", line 693, in __init__
    self._set_hostport(host, port)
  File "/usr/lib/python2.7/httplib.py", line 721, in _set_hostport
    raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
httplib.InvalidURL: nonnumeric port: '//globo.com/galeria/amazonas/a.html

怎么了?


Tags: inpy脚本urlportresponselibusr
2条回答

httplib.HttpConnection在其构造函数中获取远程URL的hostport,而不是整个URL。

对于您的用例,更容易使用urllib2.urlopen

import urllib2

with open('urls.txt') as urls:
    for url in urls:
        try:
            r = urllib2.urlopen(url)
        except urllib2.URLError as e:
            r = e
        if r.code in (200, 401):
            print '[{}]: '.format(url), "Up!"
        elif r.code == 404:
            print '[{}]: '.format(url), "Not Found!" 

这可能是一个简单的解决方案,在这里

connection = httplib.HTTPConnection(url)

您使用的是httpconnection,因此不需要提供类似于http://OSMQuote.com的url,而是需要提供OSMQuote.com

简而言之,从URL中删除http://https://,因为httplib正在考虑将:作为端口号,并且端口号必须是数字

希望这有帮助!

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