擅长:python、mysql、java
<p>下面是一个相当简单的方法:</p>
<pre><code>def startWithVowel(word):
for i, c in enumerate(word):
if c.lower() in 'aeiou':
return word[i:]
return 'No vowel'
>>> for word in 'apple', 'google', 'xyz', 'BOGGLE':
... print startWithVowel(word)
apple
oogle
No vowel
OGGLE
</code></pre>