擅长:python、mysql、java
<p>正如@RomanPekar提到的,您的算法运行缓慢,因为它的复杂性是<code>O(n^2)</code>。要修复它,您应该将其写成<code>O(n)</code>算法:</p>
<pre><code>import itertools as it
for price, prices_distinct in it.izip(prices, prices_distincts):
if prices_distinct['hash_brand_artnum'] == price['hash_brand_artnum']:
# do stuff
</code></pre>