运行Python脚本以bruteforcekeepassx时遇到的问题

Question

我试着运行下面的脚本来试图恢复KeePassX密码，问题是每次我尝试运行它时都会出现很多编程问题，而且由于我有时不是程序员（即使在研究之后），很难找到问题所在。。。在

如果您能帮我成功运行此脚本，我将不胜感激：

from winappdbg import Debug
from time import strftime
import time
import os.path

counter=0
word=""
words=[]
r_eax=0
r_ecx=0
r_edx=0

WORD_SIZE = 20

#Save the state of the registers
def action_0(event):
 global r_eax, r_ecx, r_rdx
 aThread = event.get_thread()
 r_eax = aThread.get_register("Eax")
 r_ecx = aThread.get_register("Ecx")
 r_edx = aThread.get_register("Edx")
#Write the word
def action_1( event ):
 global word
 global words
 global counter
 global WORD_SIZE

 aThread = event.get_thread()
 aProcess = event.get_process()
 memDir = aThread.get_register("Ecx")
 word=words[counter]
 word = word.replace("\n","")
 word = word[0:WORD_SIZE-1]
#word = word.lower() #optional
 aProcess.poke(memDir,word + "\0")
#Check the flag state
def action_2( event ):
 global word
 global counter
 aThread = event.get_thread()
 b = aThread.get_flag_value(aThread.Flags.Zero)
 if b:
  print 'Counter: ' + repr(counter) + ' - Correct: ' + word
  event.get_process().kill()
 else:
  print 'Counter: ' + repr(counter) + ' - Incorrect: ' + word

  if counter&lt:
   len(words)-1
   counter+=1
   aThread.set_register("Eip", 0x004D6699)
  else:
   event.get_process().kill()
#Restore the registers to the original state
def action_3( event ):
 aThread = event.get_thread()
 aThread.set_register("Eax",r_eax)
 aThread.set_register("Ecx",r_ecx)
 aThread.set_register("Edx",r_edx)
 aThread.set_register("Eip", 0x004DC395)
#Specify a dictionary here
words = open('dic.txt', "r").readlines()
print "[+] Words Loaded: ",len(words)

#Specify a key file
keyfile = "key"

try:
  debug = Debug()
  if os.path.isfile(keyfile):
    print "[+] Keyfile Loaded: '" + keyfile + "'"
    aProcess = debug.execv(['KeePass.exe', 'keepassdb.kdb', '-keyfile:' + keyfile, '-pw:'.ljust(WORD_SIZE+4)])
  else:
   print "[+] Specified keyfile '" + keyfile + "' does not exist, ignoring argument"
  aProcess = debug.execv( ['KeePass.exe', 'keepassdb.kdb', '-pw:'.ljust(WORD_SIZE+4)])

#Set the breakpoints
  debug.break_at(aProcess.get_pid() , 0x004DC395, action_0)
  debug.break_at(aProcess.get_pid() , 0x004D77A0, action_1)
  debug.break_at(aProcess.get_pid() , 0x004D6684, action_2)
  debug.break_at(aProcess.get_pid() , 0x004DC39A, action_3)

#Wait for the debugee to finish
  t1 = time.clock()
  debug.loop()

finally:
 debug.stop()

print 'Finished in ' + repr(time.clock() - t1) + ' seconds!'

运行脚本时，我得到：

^{pr2}$

注意：脚本是从http://blog.q-protex.com/2010/03/14/keepass-self-bruteforce/复制的

提前谢谢！在