为什么在我的乒乓球游戏中球不反弹？

Question

我正在尝试在Pygame中制作一个Pong克隆。我对Python相当陌生，遇到了一些麻烦。程序应该使两个球拍可以移动，球在屏幕的边缘反弹，但球没有反弹。为什么？在

bif="bg.jpg"

import pygame, sys
from pygame.locals import *

pygame.init()
pygame.display.set_caption("Griffin West's Python Pong")
pygame.mixer.init()
sounda= pygame.mixer.Sound("Music.wav")

sounda.play()

screen=pygame.display.set_mode((1280,720),0,32)
background=pygame.image.load(bif).convert()

color1=(255,255,255)
color2=(255,255,0)
color3=(0,0,255)
color4=(0,255,0)
pos1=(640,0)
pos2=(640,720)
pos3=(640,360)
pos4=(0,360)
pos5=(1280,360)
radius=(100)
x1,y1=75,0
x2,y2=1175,0
x3,y3=0,0
clock=pygame.time.Clock()
speed=750
movex1, movey1=0,0
movex2, movey2=0,0



while True:


    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        if event.type==KEYDOWN:
            if event.key==K_w:
                movey1=-2
            elif event.key==K_s:
                movey1=+2
            if event.key==K_UP:
                movey2=-2
            elif event.key==K_DOWN:
                movey2=+2
        if event.type==KEYUP:
            if event.key==K_w:
                movey1=0
            elif event.key==K_s:
                movey1=0
            if event.key==K_UP:
                movey2=0
            elif event.key==K_DOWN:
                movey2=0

    x1+=movex1
    y1+=movey1
    x2+=movex2
    y2+=movey2


    milli=clock.tick()
    seconds=milli/1000.0
    dm=seconds*speed
    x3+=dm
    y3+=dm

    if x3>1280: 
        x3+=-dm
    if y3>720:
        y3+=-dm
    if x3<0:
        x3+=dm
    if y3<0:
        y3+=dm

    screen.blit(background, (0,0))

    screen.lock()
    pygame.draw.line(screen, color1, pos1, pos2, 1)
    pygame.draw.circle(screen, color1, pos3, radius, 1)
    pygame.draw.circle(screen, color1, pos4, radius, 1)
    pygame.draw.circle(screen, color1, pos5, radius, 1)
    pygame.draw.rect(screen, color3, Rect((x1,y1),(30,100)))
    pygame.draw.rect(screen, color2, Rect((x2,y2),(30,100)))
    pygame.draw.circle(screen, color4, (int(x3),int(y3)), 15)

    screen.unlock()
    myfont = pygame.font.SysFont("Press Start 2P", 50)
    label = myfont.render("Python", 1, (255,0,0))
    screen.blit(label, (494, 115))
    myfont = pygame.font.SysFont("Press Start 2P", 50)
    label = myfont.render("Pong", 1, (255,0,0))
    screen.blit(label, (544, 175))
    pygame.display.update()

Answer 1

免责声明：我不是玩游戏的人。但是，我认为这是一个逻辑问题。在

我猜目前的行为是，球从左上角（0,0）移动到右下角（1280720），然后就停留在那里。在

你要确保当你撞到墙上时球会改变方向，所以你需要一个单独的x和y的速度（这也有助于以后，当你想要球以不同的角度移动时，这取决于球拍的击球角度）。然后，当球碰到墙上时，你改变了运动方向。在

替换此项：

dm=seconds*speed
x3+=dm
y3+=dm

if x3>1280: 
    x3+=-dm
if y3>720:
    y3+=-dm
if x3<0:
    x3+=dm
if y3<0:
    y3+=dm

使用类似的方法（通过适当的speedx初始化，speedy）：

^{pr2}$