按关键字和区域设置对列表进行排序(此处:德语元音变音符)

2024-09-28 01:25:59 发布

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我知道如何用(简单)键=函数自定义排序。但是如果我需要一个更复杂的key=函数,怎么做呢。我很难把它组装起来。在

以下是片段: 在第一个示例中,我使用key=语言环境.strxfrm这就足够了。第二个示例使用另一个key=函数(itemgetter)。但我需要两者都在一起。在

import locale
import operator

locale.setlocale(locale.LC_ALL, "")
# on my computer: German_Germany.1252

lastnames = ["Bange", "Änger", "Amman", "Änger", "Zelch", "Ösbach"]
print(sorted(lastnames, key=locale.strxfrm)) # sorted correct
                                             # alphabetically for Germany
print()

lastnames_firstnames_groups =[
    ["Bange", "Michael", 2],
    ["Änger", "Ämma", 2],
    ["Amman", "Anton", 1],
    ["Änger", "Chris", 2],
    ["Zelch", "Sven", 1],
    ["Ösbach", "Carl", 1]
]
print(sorted(lastnames_firstnames_groups, key=operator.itemgetter(2,0,1)))
# The result is sorted as I expected (the german umlaute are NOT sorted
# the correct way). Is there a way to "add" the string tranformation strxfrm
# as in the first example to this. 

有什么提示吗?在


Tags: thekey函数import示例operatorlocalesorted
2条回答

对连续键、转换键和有序键使用strxfrm:

f = operator.itemgetter(2,0,1)
print(sorted(lastnames_firstnames_groups, key=lambda x: locale.strxfrm(' '.join(str(y) for y in f(x)))))

听起来你可能想要

print(
    sorted(
        lastnames_firstnames_groups,
        key=lambda t: (t[2], strxfrm(t[0]), strxfrm(t[1]))
    )
)

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