擅长:python、mysql、java
<p>同时添加基于<code>regex</code>的解决方案:</p>
<pre><code>c = "Snap-on Power M1302A5 Imperial,IMPRL 0.062IN"
only_a = []
for word in c.split():
#print(word)
if not re.search('\d',word):
#print(word)
only_a.append(word)
' '.join(only_a)
</code></pre>
<p>输出:<code>'Snap-on Power Imperial,IMPRL'</code></p>