Python检查字符串是否包含lis中的任何元素

Question

我需要检查字符串是否包含列表中的任何元素。我正在使用此方法：

engWords = ["the", "a", "and", "of", "be", "that", "have", "it", "for", "not"]
engSentence = "the dogs fur is black and white"

print("the english sentence is: " + engSentence)

engWords2 = []
isEnglish = 0

for w in engWords:
    if w in engSentence:
        isEnglish = 1
        engWords2.append(w)

if isEnglish == 1:
    print("The sentence is english and contains the words: ")
    print(engWords2)

问题在于它给出的输出是：

^{pr2}$

如你所见，a和it不应该出现。我怎样才能搜索到它只列出单个单词，而不是一个单词的一部分？我愿意接受任何使用普通python代码或regex的想法（尽管我对python和regex都很陌生，所以请不要太复杂）谢谢。在

Answer 1

words = set(engSentence.split()).intersection(set(engWords))
if words:
    print("The sentence is english and contains the words: ")
    print(words)

将英语句子拆分成一个列表中的标记，将其转换为集合，将英语单词转换为集合，然后找到交集（公共重叠）。然后检查这是否是非空的，如果是，打印出找到的单词。在

Answer 2

找到这两个词是因为它们分别是“黑”和“白”的子串。将“in”应用于字符串时，它只查找字符的子字符串。在

尝试：

engSentenceWords = engSentence.split()

后来

^{pr2}$

它将原始句子分割成一个单字列表，然后检查整个单词的值。在

Answer 3

或者更简单，在句子和搜索词中添加空格：

engWords = ["the", "a", "and", "of", "be", "that", "have", "it", "for", "not"]
engSentence = "the dogs fur is black and white"

print("the english sentence is: " + engSentence)

engWords2 = []
isEnglish = 0
engSentence += " "

for w in engWords:
    if "%s " % w in engSentence:
        isEnglish = 1
        engWords2.append(w)

if isEnglish == 1:
    print("The sentence is english and contains the words: ")
    print(engWords2)

输出为：

^{pr2}$