PyQt:如何在QTableVi中的光标处插入文本

2024-06-28 20:07:13 发布

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我有一个QTableView如下。我想按Test按钮并在光标处插入一个“a”,例如在(row,column)=(2,2)的“11”中间。也就是说,用户双击cell(2,2)并将光标放在“11”的中间,然后按Test。期望结果:“1a1”。在

screen capture

这可行吗?如果是,怎么办?非常感谢。在

# coding: utf-8

import sys
from PyQt4 import QtGui, QtCore
from PyQt4.QtCore import *
from PyQt4.QtGui import *

MY_ARRAY = [['00', '01', '02'],
            ['10', '11', '12'],
            ['20', '21', '22']]


class MyWindow(QTableView):
    def __init__(self, *args):
        super(MyWindow, self).__init__()

        self.tablemodel = MyTableModel(MY_ARRAY)

        self.tableview = QTableView()

        self.tableview.setModel(self.tablemodel)

        self.tableview.setItemDelegate(MyDelegate(self))

        self.layout = QVBoxLayout(self)
        self.layout.addWidget(self.tableview)

        self.button1 = QPushButton("Test")

        self.button1.released.connect(self.test)

        self.layout.addWidget(self.button1)
        self.setLayout(self.layout)

    def test(self):

        # MY_ARRAY.append([30,31,32])

        index = self.tableview.currentIndex()
        item = self.tablemodel.data(index, Qt.DisplayRole)

        print("item %s " % item)

        item_edit = self.tableview.edit(index)

        qDebug("qDebug: item_edit %s " % item_edit)

        MY_ARRAY.insert(index.row(), ['30', '31', '32'])

        self.tablemodel.layoutChanged.emit()

        qDebug(" {} " .format(MY_ARRAY))

        qcursor = QCursor.pos()
        qDebug(" {} ".format(qcursor))

        qcursor1 = self.mapFromGlobal(qcursor)
        qDebug(" {} ".format(qcursor1))

        # qDebug(" self.tableview.indexAt(qcursor) {} ".format(self.tableview(qcursor)))
        # qDebug(" self.tableview.indexAt(qcursor1) {} ".format(self.tableview(qcursor1)))

        # print(' index.row(): ', index.row())

        qDebug(
            " tableview.rowViewportPosition %s " %
            self.tableview.rowViewportPosition(index.row()))
        qDebug(
            " tableview.columnViewportPosition %s " %
            self.tableview.columnViewportPosition(index.column()))

        # qDebug(" tableview.viewport() %s " % self.tableview.viewport(qcursor))

        item = self.tableview.setCurrentIndex(index)
        qDebug(" tableview.item() %s " % self.tableview)


class MyTableModel(QAbstractTableModel):
    def __init__(self, datain, parent=None, *args):
        super(MyTableModel, self).__init__(parent, *args)

        self.arraydata = datain

    def rowCount(self, parent):
        return len(self.arraydata)

    def columnCount(self, parent):
        return len(self.arraydata[0])

    def data(self, index, role):
        if not index.isValid():
            return None

        elif not (role == Qt.DisplayRole or role == Qt.EditRole):
            return None
        return (self.arraydata[index.row()][index.column()])

    def setData(self, index, value, role=Qt.EditRole):
        self.arraydata[index.row()][index.column()] = value
        return True

    def flags(self, index):
        return Qt.ItemIsEditable | Qt.ItemIsEnabled | Qt.ItemIsSelectable


class MyDelegate(QStyledItemDelegate):

    def __init__(self, parent=None):
        super(MyDelegate, self).__init__(parent)

    def createEditor(self, parent, option, index):
        editor = QLineEdit(parent)
        self.connect(editor, SIGNAL("returnPressed()"),
                     self.commitAndCloseEditor)
        return editor

    def commitAndCloseEditor(self):
        editor = self.sender()
        if isinstance(editor, (QTextEdit, QLineEdit)):
            self.emit(SIGNAL("commitData(QWidget*)"), editor)
            self.emit(SIGNAL("closeEditor(QWidget*)"), editor)

    def setEditorData(self, editor, index):
        text = index.model().data(index, Qt.DisplayRole)

        editor.setText(text)

    def setModelData(self, editor, model, index):
        model.setData(index, editor.text())

def main():
    app = QApplication(sys.argv)
    w = MyWindow()
    w.show()
    sys.exit(app.exec_())

if __name__ == "__main__":
    main()

Tags: selfindexreturninitmydefitemqt
2条回答

经过一番挣扎和使用qDebug,我终于找到了一个解决方案。我相信它还可以进一步改进。但我对PyQt了解不多。其思想是在关闭编辑器之前将光标位置缓存到MyDelegate(QStyledItemDelegate)。我希望它能对遇到同样问题的人有所帮助。在

class MyDelegate(QStyledItemDelegate):
    ...
    def createEditor(self, parent, option, index):
        self.cursorpos = -1  # unset flag
        editor = QLineEdit(parent)
        self.connect(editor, SIGNAL("editingFinished()"),
                         self.commitAndCloseEditor)
        return editor

    def commitAndCloseEditor(self):
        editor = self.sender()
        self.cursorpos = editor.cursorPosition()
        if isinstance(editor, (QTextEdit, QLineEdit)):
            self.emit(SIGNAL("commitData(QWidget*)"), editor)
            self.emit(SIGNAL("closeEditor(QWidget*)"), editor)

整件事如下所述。在

^{pr2}$

表格单元格没有光标,不能直接编辑。编辑功能由项目委托提供。默认情况下,用于文本数据的编辑器小部件是QLineEdit,但其他数据类型可能使用不同的编辑器小部件,例如用于数值数据的QSpinBox,或用于布尔数据的QComboBox。可以通过设置custom item-delegate来控制使用的特定小部件。在

使用按钮之类的东西在编辑小部件中插入文本的最大问题是,只要单击按钮,编辑器就会自动关闭(并销毁)。因此,使用上下文菜单添加自定义操作要简单得多:

class MyWindow(QTableView):
    def __init__(self, *args):
        ...
        self.delegate = MyDelegate(self)
        self.delegate.contextMenuRequested.connect(self.showContextMenu)
        self.tableview.setItemDelegate(self.delegate)

    def showContextMenu(self, editor, pos):
        pos = editor.mapToGlobal(pos)
        menu = editor.createStandardContextMenu()
        menu.addSeparator()
        action = menu.addAction('Insert Text')
        if menu.exec_(pos) is action:
            editor.insert(' foo ')

class MyDelegate(QStyledItemDelegate):
    contextMenuRequested = pyqtSignal(object, QPoint)

    def createEditor(self, parent, option, index):
        editor = QLineEdit(parent)
        editor.setContextMenuPolicy(Qt.CustomContextMenu)
        editor.customContextMenuRequested.connect(
            lambda pos: self.contextMenuRequested.emit(editor, pos))
        return editor

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