Python和Hypertermin中RS232串行对话中的ASCII-Hex转换

Question

我正在用Python通过RS232串行对话从仪器上进行数据传输。数据是ASCII格式的。例如，这是我使用Python从仪器中获得的ASCII信息：

'\x02S20390908127F010102F3004000900300000000000000000000000000000300A500000000000202020202020206070505050505050000000707070707070707020700000000000000000000000000000000000000008000800089237A0715047E000000000000000000000000000000000000000000000000000000000000000000000000005350374646303030\x1732'

使用超级终端（Docklight）进行的相同数据传输给了我这个结果，下面是我在超级终端中得到的十六进制表示：

^{pr2}$

我的问题是，如何使用Python从ascii数据中获得相同的十六进制表示。说到这类事，我是个无名小卒。提前谢谢你。在

Answer 1

说明：使用ord将每个字符转换为字节，然后将其格式化为两位数的十六进制数并将其输入到一个列表中。然后使用空格作为分隔符加入列表。在

>>> ll = ["%02X" % (ord(x)) for x in '\x02S20390908127F010102F3004000900300000000000000000000000000000300A500000000000202020202020206070505050505050000000707070707070707020700000000000000000000000000000000000000008000800089237A0715047E000000000000000000000000000000000000000000000000000000000000000000000000005350374646303030\x1732']
>>> ll           #as a list
['02', '53', '32', '30', '33', '39', '30', '39', '30', '38', '31', '32', '37', '46', '30', '31', '30', '31', '30', '32', '46', '33', '30', '30', '34', '30', '30', '30', '39', '30', '30', '33', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '33', '30', '30', '41', '35', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '36', '30', '37', '30', '35', '30', '35', '30', '35', '30', '35', '30', '35', '30', '35', '30', '30', '30', '30', '30', '30', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '32', '30', '37', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '38', '30', '30', '30', '38', '30', '30', '30', '38', '39', '32', '33', '37', '41', '30', '37', '31', '35', '30', '34', '37', '45', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '35', '33', '35', '30', '33', '37', '34', '36', '34', '36', '33', '30', '33', '30', '33', '30', '17', '33', '32']
>>> ' '.join(ll) # as a string
'02 53 32 30 33 39 30 39 30 38 31 32 37 46 30 31 30 31 30 32 46 33 30 30 34 30 30 30 39 30 30 33 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 33 30 30 41 35 30 30 30 30 30 30 30 30 30 30 30 32 30 32 30 32 30 32 30 32 30 32 30 32 30 36 30 37 30 35 30 35 30 35 30 35 30 35 30 35 30 30 30 30 30 30 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 32 30 37 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 38 30 30 30 38 30 30 30 38 39 32 33 37 41 30 37 31 35 30 34 37 45 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 35 33 35 30 33 37 34 36 34 36 33 30 33 30 33 30 17 33 32'

Answer 2

这似乎是最简单的方法。。。在

ascstr = 'x\02S20..."  #your string

#I think you need to get rid of the first 4 characters '\x02' looks like
#it is hex
ascstr = ascstr[4:] 
for c in mystring:
   hexstr = hexstr + hex(ord(c))[2:] + ' '