擅长:python、mysql、java
<p>字典(或集合。计数器)比numpy数组更快地检查当前项目。在</p>
<p>因此,如果输出顺序不重要:</p>
<pre><code>from collections import Counter
c = Counter()
A = [(2, 2, 0), (1, 5, 0), (6, 8, 0), (2, 2, 2) ]
for a in A:
c[a[:2]] += a[2]
B = [list(k) + [v] for k,v in c.iteritems()]
</code></pre>
<p><code>B</code>现在是:</p>
^{pr2}$