擅长:python、mysql、java
<p>坚持你的方法,你可以这样做</p>
<pre><code>arr = np.array([np.where(keywords['keywords'].str.contains(k), v, 'No Match') for k, v in labels.items()]).T
keywords["Labels"] = ["|".join(set(item[ind if ind.sum() == ind.shape[0] else ~ind])) for item, ind in zip(arr, (arr == "No Match"))]
Out[97]:
keywords Labels
0 cheap shoes budget
1 luxury shoes expensive
2 cheap hiking shoes sport|budget
</code></pre>