我需要根据条件对包含嵌套列表的列表进行排序。条件是:如果第一个索引为0,则对索引nr 7排序。如果第二个索引为0,则按索引nr 8排序。所以下面的列表(未排序):
[[11, 37620, 'mat', 'xxx', 1, 28.5, 0, 11, 37620, 'Arp', 'xxx', 1, 28],
[10, 24210, 'Skatt', 'xxx', 2, 40, 0, 0, 0, 0, 0, 0, 0],
[10, 37010, 'test, a', 'xxx', 5, 36.75, 0, 10, 37010, '', 'xxx', 7, 50.75],
[0, 0, 'mottagare', 'xxx', 3, 20.25, 0, 10, 21511, 0, 0, 0, 0],
[10, 40000, 'eld', 'xxx', 5, 30.5, 0, 10, 40000, 'Oly', 'xxx', 5, 30],
[10, 17060, 'bok', 'xxx', 1, 28.5, 0, 0, 0, 0, 0, 0, 0]]
应该是这样的:
^{pr2}$我试过用_列表.排序(key=itemgetter(0))和lambda,但0总是先结束。我已经用冒泡排序解决了这个问题,但是它已经非常慢了,列表中有6000个元素。我把泡泡糖贴在下面以供参考。列表零值最初是None
,但是为了在python3中进行排序,我将它们转换为int0。在
the_list_pos = 0
for key, value in kund_dict2.items():
# Start sorting from the whole list, since the_list_pos is zero
for passnum in range(len(komplett_lista)-1,the_list_pos,-1):
# Loop the list, one by one
for i in range(passnum):
# If these helper variables are None at the end, nothing happens
comp1 = None
comp2 = None
# Check that the variables to compare are not None, and set them to appropiate values
if komplett_lista[i][0] is not None and komplett_lista[i][0] == key:
comp1 = komplett_lista[i][1]
elif komplett_lista[i][7] is not None and komplett_lista[i][7] == key:
comp1 = komplett_lista[i][8]
if komplett_lista[i+1][0] is not None and komplett_lista[i+1][0] == key:
comp2 = komplett_lista[i+1][1]
elif komplett_lista[i+1][7] is not None and komplett_lista[i+1][7] == key:
comp2 = komplett_lista[i+1][8]
# Do the actual sorting
if comp1 is not None and comp2 is not None:
if comp1 > comp2:
temp = komplett_lista[i]
komplett_lista[i] = komplett_lista[i+1]
komplett_lista[i+1] = temp
# update the position so that we do not sort over the already sorted data
the_list_pos += (value)
如有任何解决此问题的建议,我们将不胜感激!在
编写一个函数来包含查找排序依据的列的逻辑:
然后将此函数用作
^{pr2}$key
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