球面Python的密度图

2024-06-28 19:00:22 发布

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如果我有对应于球坐标中给定点(θ,phi)的值数组,如何在球面上绘制密度图?我发现了如何构造一个球体,例如Bloch sphereplotting on a sphere。第一个例子是非常好看的-轴是需要和热图。在


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1楼 · 发布于 2024-06-28 19:00:22

如果您将QuTipBloch类的子类化,并更改它绘制球体的方式,则可以绘制密度图并保留它创建的所有其他框架。在

获取^{} examples,并更改Bloch类的绘图函数。把它放在你自己的子类中可以防止你对库进行黑客攻击。在

from qutip import Bloch
from math import sqrt, sin, cos, pi
from colorsys import hsv_to_rgb


from numpy import linspace, outer, ones, sin, cos, arccos, arctan2, size, empty
class BlochDensity(Bloch):
  def plot_back(self):
    # back half of sphere
    u = linspace(0, pi, 25)
    v = linspace(0, pi, 25)
    x = outer(cos(u), sin(v))
    y = outer(sin(u), sin(v))
    z = outer(ones(size(u)), cos(v))

    colours = empty(x.shape, dtype=object)
    for i in range(len(x)):
      for j in range(len(y)):
        theta = arctan2(y[i,j], x[i,j])
        phi = arccos(z[i,j])

        colours[i,j] = self.density(theta, phi)


    self.axes.plot_surface(x, y, z, rstride=1, cstride=1,
                           facecolors=colours,
                           alpha=self.sphere_alpha, 
                           linewidth=0, antialiased=True)
    # wireframe
    self.axes.plot_wireframe(x, y, z, rstride=5, cstride=5,
                             color=self.frame_color,
                             alpha=self.frame_alpha)
    # equator
    self.axes.plot(1.0 * cos(u), 1.0 * sin(u), zs=0, zdir='z',
                   lw=self.frame_width, color=self.frame_color)
    self.axes.plot(1.0 * cos(u), 1.0 * sin(u), zs=0, zdir='x',
                   lw=self.frame_width, color=self.frame_color)



  def plot_front(self):
    # front half of sphere
    u = linspace(-pi, 0, 25)
    v = linspace(0, pi, 25)
    x = outer(cos(u), sin(v))
    y = outer(sin(u), sin(v))
    z = outer(ones(size(u)), cos(v))

    colours = empty(x.shape, dtype=object)
    for i in range(len(x)):
      for j in range(len(y)):
        theta = arctan2(y[i,j], x[i,j])
        phi = arccos(z[i,j])

        colours[i,j] = self.density(theta, phi)


    self.axes.plot_surface(x, y, z, rstride=1, cstride=1,
                           facecolors=colours,
                           alpha=self.sphere_alpha, 
                           linewidth=0, antialiased=True)


    # wireframe
    self.axes.plot_wireframe(x, y, z, rstride=5, cstride=5,
                             color=self.frame_color,
                             alpha=self.frame_alpha)
    # equator
    self.axes.plot(1.0 * cos(u), 1.0 * sin(u),
                   zs=0, zdir='z', lw=self.frame_width,
                   color=self.frame_color)
    self.axes.plot(1.0 * cos(u), 1.0 * sin(u),
                   zs=0, zdir='x', lw=self.frame_width,
                   color=self.frame_color)

我在这里所做的是让绘图部分调用BlochDensity:self.density(theta, phi)的函数,我还没有定义这个函数。在

创建BlochDensity对象后,需要创建该函数,即theta, phi到密度的映射。我建议使用SciPy's 2D interpolation创建函数,如下所示:

^{pr2}$

enter image description here

如果要提高分辨率,那么只需在BlochDensityplot_*函数内更改linspace中的数字。在

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