如何将图片保存到具有图片url的mongodb?

2024-09-26 17:59:08 发布

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我有以下问题:我需要在网页抓取期间将图片保存到mongodb。我有一个图像链接。我试过了:

images_binaries = [] # this will store all images data before saving it to mongodb
# save as file on hard disc
urllib.urlretrieve(url, self.album_path + '/' + photo_file_name)
images_binaries.append(open(self.album_path + '/' + photo_file, 'r').read())
....
# after that I append this array of images raw data to Item
post = WaralbumPost()
post['images_binary'] = images_binaries
....

Waralbum项目代码:

^{pr2}$

但这会导致在保存到mongo时出错:bson.errors.InvalidStringData: strings in documents must be valid UTF-8: '\xff\.....

有什么更好的方法?转换原始图像数据能解决这个问题吗?也许,斯帕蒂有保存图像的好方法? 谢谢你的回答

解决方案: 我删除了这几行: 图像_二进制文件.append(打开(self.album_路径+'/'+照片\文件,'r').read()) post['images_binary']=images_二进制文件 在我的WaralbumPost中,我还保存了图像url。比,在管道.py我得到这个网址并在mongo中保存图像。代码管道.py公司名称:

class WarAlbum(object):
def __init__(self):
    connection = pymongo.Connection(settings['MONGODB_SERVER'], settings['MONGODB_PORT'])
    db = connection[settings['MONGODB_DB']]
    self.collection = db[settings['MONGODB_COLLECTION']]
    self.grid_fs = gridfs.GridFS(getattr(connection, settings['MONGODB_DB']))

def process_item(self, item, spider):
    links = item['img_links']
    ids = []
    for i, link in enumerate(links):
        mime_type = mimetypes.guess_type(link)[0]
        request = requests.get(link, stream=True)
        _id = self.grid_fs.put(request.raw, contentType=mime_type, filename=item['local_images'][i])
        ids.append(_id)
    item['data_chunk_id'] = ids
    self.collection.insert(dict(item))
    log.msg("Item wrote to MongoDB database %s/%s" %
            (settings['MONGODB_DB'], settings['MONGODB_COLLECTION']),
            level=log.DEBUG, spider=spider)
    return item

希望,这对某人有帮助


Tags: 文件to图像selfdataalbumsettingsmongodb
1条回答
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1楼 · 发布于 2024-09-26 17:59:08

使用GridFS。Example:

String newFileName = "my-image";
File imageFile = new File("/users/victor/images/image.png");
GridFS gfsPhoto = new GridFS(db, "photo");
GridFSInputFile gfsFile = gfsPhoto.createFile(imageFile);
gfsFile.setFilename(newFileName);
gfsFile.save();

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