Python:通过引用传递套接字

Question

我是python新手，我必须用python编写我的第一个任务。我保证做完这件事后我会把它从头学到尾，但我现在需要你的帮助。在

我的代码当前如下所示：

comSocket.send("\r")
sleep(1)
comSocket.send("\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

comSocket.send("\r\r")
sleep(2)
comSocket.settimeout(8)
try:
   comSocket.recv(256)
except socket.timeout:
   errorLog("[COM. ERROR] Station took too long to reply. \n")
   comSocket.shutdown(1)
   comSocket.close()
   sys.exit(0)

errorLog是另一种方法。我想通过创建一个新方法来重写这段代码，这样我就可以传递message，引用socket，然后{}从套接字接收到的内容。在

有什么帮助吗？在

谢谢：）

Answer 1

一个简单的解决方案是

def socketCom(comSocket, length, message, time):
    comSocket.send(message)
    comSocket.settimeout(8)
    if (time != 0):
        sleep(time)
    try:
        rawData = comSocket.recv(length)
    except socket.timeout:
        errorLog("[COM. ERROR] Station took too long to reply. \n")
        comSocket.shutdown(1)
        comSocket.close()
        sys.exit(0)

    return rawData