打印关键字，如果满足条件，则打印关键字值

Question

我想创建简单的“编码脚本”

我有这本字典：

diction =  {
"A" :  "Z", 
"Y" :  "B",
"C" :  "X"
}

我想给出一些随机的句子，重复它的字母，如果在这本字典中找到字母-打印相反的字母
所以，如果我说

"ABC"

它应返回：

"ZYX"

我尝试了此代码，但出现了一个“KeyError”：

# Defining dictionary
diction =  {
"A" :  "Z", 
"Y" :  "B",
"C" :  "X",
"W" :  "E",
"E" :  "V",
"U" :  "F",
"G" :  "T",
"S" :  "H",
"I" :  "R",
"Q" :  "J",
"K" :  "P",
"O" :  "L",
"M" :  "N",
" " :  " "
}

# Sentence in "szyfr" variable should be split into list.

szyfr = "SOME SENTENCE WHATEVER"

def split(szyfr): 
     return [char for char in szyfr]

szyfr = split(szyfr)


# Now I want to iterate through "szyfr" and replace letters as in "CAT" example:  

for i in szyfr:
        if i in diction:
                
                diction = {x:y for x,y in diction.items()}
                print(i)
                print("Variable: " + i + " is in 'key'")
                pass
        elif diction[i] in szyfr:
                diction = {y:x for x,y in diction.items()}
                print(i)
                print("Variable: " + i + " is in 'value'")
        elif i is " ":
                pass

print(szyfr)

Answer 1

如果您确实想使用一个dict，其中每个键的“字母”都有“相反字母”的值：

这是一个可能的解决方案：

diction = {" ": " "}

all_letters = range(ord('A'), ord('Z')+1)
for char, opsite_char in zip(all_letters, reversed(all_letters)):
    diction[chr(char)] = chr(opsite_char)

print(diction)

输出：

{' ': ' ', 'A': 'Z', 'B': 'Y', 'C': 'X', 'D': 'W', 'E': 'V', 'F': 'U', 'G': 'T', 
'H': 'S', 'I': 'R', 'J': 'Q', 'K': 'P', 'L': 'O', 'M': 'N', 'N': 'M', 'O': 'L', 
'P': 'K', 'Q': 'J', 'R': 'I', 'S': 'H', 'T': 'G', 'U': 'F', 'V': 'E', 'W': 'D', 
'X': 'C', 'Y': 'B', 'Z': 'A'}