如何根据列表中的内容将列表分为2？

Question

所以我得到了这份名单

list = ["m2010","n1950","m1834","n993","m1490"]

我想让代码将列表分成2部分，应该是这样的：

n_list = ["n1950","n993"]

m_list = ["m2010","m1834","m1490"]

所有以“n”开头的词都在n_list中，而以“m”开头的词都在m_list中，但我太笨了，不能自己做

Answer 1

你可以做的一件事是制作一本字典，其中的关键字是单词的第一个字母

list = ["m2010","n1950","m1834","n993","m1490"]

def split(x):
    d = dict()
    for word in x:
       first = word[0]
       if first in d.keys():
            d[first].append(word)
       else:
            d[first] = [word]
    return d

split_lists = split(list)
print(split_lists['m'])
print(split_lists['n'])

Answer 2

list = ["m2010", "n1950", "m1834", "n993", "m1490"]

n_list = [item for item in list if item[0] == 'n']
m_list = [item for item in list if item[0] == 'm']

Answer 3

list = ["m2010","n1950","m1834","n993","m1490"]
n_list = []
m_list = []

for i in list:
    if i[:1]=='m':
        m_list.append(i)
    elif i[:1]=='n':
        n_list.append(i)
print(m_list)
print(n_list)