从2个元组列表中查找公共值，并将一个元组中的值添加到另一个元组中

Question

我有两个以元组为元素的列表。元组的一个元素将与其他列表中的元组匹配，并将相应的配置值从一个元组添加到另一个元组

我的两份清单是：

l1 = [('Receipt total', 10),('Total Amount (AED)', 10),('Grand total', 10),('Net Amount', 9),
 ('Total Amount', 9),('Total (words are in between)', 6)]

l2 = [('Total Amount', ['593.52']), ('Total (words are in between)', ['593.52'])]

l2中的键Total Amount和Total (words are in between)将与l1匹配，并且在这种情况下，分别与l1 9和6中存在的键对应的值将被添加到l2或新列表中

预期产出：

l2 = [('Total Amount', ['593.52'],[9]), ('Total (words are in between)', ['593.52'],[6])]

我很乐意提供进一步的澄清，我无法想象这会发生，如果这看起来太混乱，我很抱歉，我寻找类似的问题，但没有什么是合适的 谢谢大家!

Answer 1

为了便于阅读，我会创建一个l1的临时字典，以便更容易地查找键

解压l2中的元组，并将键与l1-字典中的键进行比较。如果匹配并将所有内容包装到列表中，则创建一个新元组

l1_map = {k: v for k, v in l1}
l2_updated = [(key, num, [l1_map[key]]) for key, num in l2 if key in l1_map]

结果:

[('Total Amount', ['593.52'], [9]),
 ('Total (words are in between)', ['593.52'], [6])]

Answer 2

首先从l1创建dict，然后更改l2：

D1=dict(l1)
l2=[t + ([D1[t[0]]],) for t in l2]

输出：

[('Total Amount', ['593.52'], [9]), ('Total (words are in between)', ['593.52'], [6])]