2024-10-03 02:37:42 发布
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friends_filter = ["Osama", "Wessam", "Amal", "Essam", "Gamal", "Othman"] namess = filter(lambda names: names if names[-1].lower() == 'm', friends_filter) for name in namess: print(name)
为什么它在列表名之前给我错误(语法错误)
谓词只需返回比较结果,而不必返回值本身
friends_filter = ["Osama", "Wessam", "Amal", "Essam", "Gamal", "Othman"] namess = filter(lambda names: names[-1].lower() == 'm', friends_filter) for name in namess: print(name)
出现语法错误,因为内联if需要else语句。但在lambda表达式中不必使用内联if if names[-1].lower() == 'm' else None
if names[-1].lower() == 'm' else None
谓词只需返回比较结果,而不必返回值本身
出现语法错误,因为内联if需要else语句。但在lambda表达式中不必使用内联if
if names[-1].lower() == 'm' else None
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