擅长:python、mysql、java
<p>让它更像这样怎么样:</p>
<pre><code>adminPass = 'asdf' # just put this in for testing purposes
tries = 0
while True:
inputPass=str(input("Input doctor's password:(see line 1 of code) "))
if inputPass == adminPass:
passwordCorrect = True
else:
passwordCorrect = False
print("Wrong password! Only "+str(2-tries)+" tries left.")
tries += 1
if tries > 1:
print("Wrong password! Permission denied.")
break
if passwordCorrect:
print("Permission granted...")
print(" ")
break
</code></pre>