python：在每个子字符串后面的2个位置插入一个字符

Question

我有一个字符串：'51.6251.8750.6951.4651.462626200'，我想得到这样一个列表：['51.62', '51.87', '50.69', '51.46', '51.46', '2626200']

所以，基本上，在找到一个点之后，字符串应该被拆分2个位置

现在，我有以下内容，在这里我创建了一个所有点位置的列表，不确定是否是这样

import re

string = '51.6251.8750.6951.4651.462626200'

k = 2

# I couldn't find the position of the dot actually, so I had to replace for something first, it may be unecessary

subString = '-'

replacedString = re.sub('[.]', subString, string)

# create a list with all positions of the substring

subStringPosition = [i.start() for i in re.finditer(subString, replacedString)]

# add k to each element of the subStringPosition

subStringAfterK = [x + k for x in subStringPosition]

如果有人能帮助我，我将不胜感激

Answer 1

对于不使用re的解决方案：

def split(s):
    nums = []
    while "." in s:
        i = s.find(".")
        n = s[:i+3]
        s = s[i+3:]
        nums.append(n)
    if s:
        nums.append(s)
    return nums