如果存在特定单词，则从括号中删除文本

Question

我有两个字符串，如果括号内有某个单词，我会尝试删除括号内的文本。对于s1，我可以使用下面的正则表达式获得所需的输出，但对于s2，相同的逻辑不起作用。不知道出了什么问题

s1 = '((Xyz_lk eou ) some stuff (XYZ_l))) (vc vbn XyZ no.s)'
s2 = '( 100 % eou ) - 1h-imidazole 5,5- [ 1,1 -biphenyl ] -4,4 -diylbis [ 2 -- 2-pyrrolidinyl ] hydrochloride'

逻辑：

vc1 = re.sub(r"\s*\((\w|\s)*(eou|eou)(\w|\s)*\)", "", s1)
print(vc1)
vc2 = re.sub(r"\s*\((\w|\s)*(eou|eou)(\w|\s)*\)", "", s2)
print(vc2)

输出

vc1: (some stuff (XYZ_l))) (vc vbn XyZ no.s)
vc2: ( 100 % eou ) - 1h-imidazole 5,5- [ 1,1 -biphenyl ] -4,4 -diylbis [ 2 -- 2-pyrrolidinyl ] hydrochloride

Answer 1

这能解决你的问题吗

vc1 = re.sub(r"\([^())]*eou[^)]*\)", "", s1)
print(vc1)
==> ( some stuff (XYZ_l))) (vc vbn XyZ no.s)


vc1 = re.sub(r"\([^())]*eou[^)]*\)", "", s2)
print(vc1)
==>  - 1h-imidazole 5,5- [ 1,1 -biphenyl ] -4,4 -diylbis [ 2   2-pyrrolidinyl ] hydrochloride