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<pre><code># all ingredients, represented by numbers: 0= empty selection 1=rice 2=spice 3=vegetable
allIng = [0,1,2,3]
#Each individual recipe(r)
# Veggie Rice Balls
r1 = (0,1,3)
# Curry Rice
r2 =(0,1,2)
# Herb Sauté
r3 = (0,2,3)
# Vegetable Curry
r4 = (1,2,3)
# all recipes on one list
allRec = [r1,r2,r3,r4]
allRecNames = {(0,1,3): 'Veggie Rice Balls', (0,1,2): 'Curry Rice', (0,2,3): 'Herb Sauté', (1,2,3): 'Vegetable Curry'}
#ingredients picked
iP = []
#ingredient count
iC = 1
#User given option to pick up to 3 ingredients
while iC <= 3:
pitem = int (input ("Pick up to 3 items "))
if pitem in allIng:
iP.append(pitem)
print(iP)
iC += 1
else:
print ("Incorrect entry, please pick again")
#sort list
iP.sort()
iP = tuple(iP)
#compare iP to allRec looking for matches
if iP in allRec:
match = set ([iP]) & set(allRec)
print ("Match:",match)
allRecNames[match]
</code></pre>
<p>大家好</p>
<p>试着让我的代码打印出与它们各自匹配的菜肴的名称。例如,如果我输入0,1,3,我会得到素食饭团</p>
<p>当前获取错误:TypeError:不可损坏的类型:“set”</p>
<p>如果我错了,请纠正我的错误和ELI5,但这是否意味着我需要将匹配项转换为可哈希的内容:</p>
<pre><code> allRecNames[match]
</code></pre>
<p>之前有人在我的代码中推荐了元组转换,并认为我也可以在这里做类似的事情,但没有得到任何线索和错误</p>
<p>和往常一样,如果这是一个愚蠢的帮助,任何帮助都是感激和抱歉的</p>