如何迭代列表并将字典附加到另一个列表

Question

lst = ['12233223','13232423','23453443']

我看起来像这样：

new_list = [{'id':'12233223', 'new_id':'d2233223'},{'id':'13232423','new_id':'d3232423'}]

但我明白了

[{'id':13453443,'new_id':13453443},{'id':13453443,'new_id':13453443}]

这是我的密码

lst = [{'id':'12233223'},{'id':'13232423',} {'id':'23453443'}]
d={}
new_list=[]
for each in lst:
    d['id']= each
    if len(each)==8 and each[0]==1:
    new_id = each.replace('1','d',1)
    d['new_id'] = new_id
    new_list.append(d)

Answer 1

这个简单的版本怎么样。相反，您只需将'd'添加到string[1:]-

[{'id':i,'new_id':'d'+i[1:]} for i in lst]

[{'id': '12233223', 'new_id': 'd2233223'},
 {'id': '13232423', 'new_id': 'd3232423'},
 {'id': '23453443', 'new_id': 'd3453443'}]

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编辑：刚刚看到您的if状况。更新如下：

[{'id':i,'new_id':'d'+i[1:]} for i in lst if i[0] if i[0]=='1' and len(i)==8]

[{'id': '12233223', 'new_id': 'd2233223'},
 {'id': '13232423', 'new_id': 'd3232423'}]