t_codes = ["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]
t_names = ["Outsite", "NewFm", "CUSTOMER-IN"]
上面提到的是我最初的输入列表
我需要通过将t_名称的每个元素与t_代码的每个元素匹配来从t_代码创建2个列表,以创建-
清单1是
["11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator" , "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]
此列表包含不包含t_名称中提到的任何字符串的所有元素
清单2是
["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin",
"11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin",
"22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin" ]
此列表包含t_名称中的Outsite、NewFm和CUSTOMER-IN字符串
我尝试的是:
does_contain = []
doesnt_contain = []
for tool in t_names:
for team in t_codes:
if bool(re.search(tool, team)):
does_contain.append(team)
else:
doesnt_contain.append(team)
print(does_contain)
print("-------------")
print(doesnt_contain)
由于明显的原因,这并没有给我预期的输出。请帮忙
依我看,你正在寻找
any(...)
:这将为您的给定输入生成:
您应该将列表转换为
set
类型。set
类型本机具有此类操作相关问题 更多 >
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