在Python中将值从列表分配到字典，而不使用for循环

Question

我需要不使用任何循环的相同输出

我有两份清单：

groupVal = ["Staff 1","Staff 2"]
nameValue = ["ABC","XYZ"]

我的代码如下所示：

sdict = {"group": {}}
for index, item in enumerate(groupVal):
    sdict ['group'][item] = {"name": "Hi "+nameValue[index], "approval" :"yes"}

sdict的产出：

{'group': {'Staff 1': {'name': 'Hi ABC', "approval" :"yes"}, 'Staff 2': {'name': 'Hi XYZ', "approval" :"yes"}}}

Answer 1

更妙的是，整个sdict只有一行

groupVal = ["Staff 1","Staff 2"]
nameValue = ["ABC","XYZ"]

sdict = {'group': {item: {'name': 'Hi ' + value, 'approval': 'yes'} for item, value in zip(groupVal, nameValue)}}

sdict
{'group': {
    'Staff 1': {'name': 'Hi ABC', 'approval': 'yes'},
    'Staff 2': {'name': 'Hi XYZ', 'approval': 'yes'}
  }
}