为什么我要得到范围误差的索引？

Question

def oburparaust(liste, money):
moneycontrol = 0.0
coin=0
control = 0
while True:
    if liste[control] > money:
        control+=1
    else:
        moneycontrol+=liste[control]
        coin+=1
        if moneycontrol==money:
            break
        elif moneycontrol > money:
            moneycontrol-=liste[control]
            coin-=1
            print(moneycontrol)
            if control>len(liste)-1:
                print(moneycontrol)
                control=len(liste)-1
            else:
                control+=1
    #print(coin)
oburparaust([1.0, 0.50, 0.25, 0.10, 0.05, 0.01], 5.38)

我想计算一下5.38的硬币用了多少钱。但是我得到了范围错误的索引，我找不到为什么我要在列表上做什么

错误

Traceback (most recent call last):
     File "xxxx", line 26, in 
     oburparaust([1.0, 0.50, 0.25, 0.10, 0.05, 0.01], 5.38)
     File "xxxx", line 6, in oburparaust
     if liste[kontrol] > a:
     IndexError: list index out of range
     moneycontrol:  1.0    Coin:  1
     moneycontrol:  2.0    Coin:  2
     moneycontrol:  3.0    Coin:  3
     moneycontrol:  4.0    Coin:  4
     moneycontrol:  5.0    Coin:  5
     moneycontrol:  5.0    Coin:  5
     moneycontrol:  5.0    Coin:  5
     moneycontrol:  5.25    Coin:  6
     moneycontrol:  5.25    Coin:  6
     moneycontrol:  5.35    Coin:  7
     moneycontrol:  5.35    Coin:  7
     moneycontrol:  5.35    Coin:  7
     moneycontrol:  5.359999999999999    Coin:  8
     moneycontrol:  5.369999999999999    Coin:  9
     moneycontrol:  5.379999999999999    Coin:  10
     moneycontrol:  5.379999999999999    Coin:  10

Answer 1

您的列表“liste”包含6项，这意味着您的索引以0开始，以5结束，当变量控件的值为6时，索引将超出范围。如果变量“control”小于列表“liste”的长度，则需要控制该变量。比如：

def oburparaust(liste, money):
    moneycontrol = 0.0
    coin=0
    control = 0
    while control < len(liste):
           . . .