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<p>我有两个列表，我想返回一个新列表，其中每个列表都是从第一个列表中选择一个项目，从第二个列表中最多选择两个项目：
从实例：</p>
<pre><code>vaccinate_list: [('vaccinate', (2, 3)), ('vaccinate', (8, 1))]
quarantine_list: [('quarantine', (6, 3)), ('quarantine', (3, 4)), ('quarantine', (0, 1))]
</code></pre>
<p>将返回（不带新行）：</p>
<pre><code>allCombinations = [
[('vaccinate', (2, 3))],
[('vaccinate', (8, 1))],
[('vaccinate', (2, 3)), ('quarantine', (6, 3))],
[('vaccinate', (2, 3)), ('quarantine', (3, 4))],
[('vaccinate', (2, 3)), ('quarantine', (0, 1))],
[('vaccinate', (8, 1)), ('quarantine', (6, 3))],
[('vaccinate', (8, 1)), ('quarantine', (3, 4))],
[('vaccinate', (8, 1)), ('quarantine', (0, 1))],
[('vaccinate', (2, 3)), ('quarantine', (6, 3)), ('quarantine', (3, 4))],
[('vaccinate', (2, 3)), ('quarantine', (6, 3)), ('quarantine', (0, 1))],
[('vaccinate', (2, 3)), ('quarantine', (3, 4)), ('quarantine', (0, 1))],
[('vaccinate', (8, 1)), ('quarantine', (6, 3)), ('quarantine', (3, 4))],
[('vaccinate', (8, 1)), ('quarantine', (6, 3)), ('quarantine', (0, 1))],
[('vaccinate', (8, 1)), ('quarantine', (3, 4)), ('quarantine', (0, 1))]
]
</code></pre>
<p>我试过使用intertools组合，但很挣扎，
请帮忙</p>
