程序将whileloop输入的数字平方添加到列表中

Question

我正在编写一个程序，它应该产生如下输出：

`Enter an integer (or Q to quit): 1
Enter an integer (or Q to quit): 2
Enter an integer (or Q to quit): 3
Enter an integer (or Q to quit): Q
(1 x 1) + (2 x 2) + (3 x 3) = 14`

到目前为止，我已经得到了正确的方程显示，但我似乎不知道如何实际得到方程的总数。目前，总数显示为18，而不是预期的14

以下是我目前的代码：

`int_list = [] # initiate list 

while True:
  user_input = input("Enter an integer (or Q to quit): ") # get user input
  if user_input == "Q": # break loop if user enters Q
    break
  integer = int(user_input) # convert user_input to an integer to add to list
  int_list.append(integer) # add the integers entered to the list

for i in range(0, len(int_list)):
  template = ("({0} x {1})".format(int_list[i], int_list[i]))
  if i == len(int_list)-1:
    trailing = " = "
  else:
    trailing = " + "
  print(template, end="")
  print(trailing, end="")

for i in range(0, len(int_list)):
  x = (int_list[i]*int_list[i])

add = (x+x)
print(add)`

任何帮助都将不胜感激：））

Answer 1

你可以试试这个

state= True
combi= []
while state:
    user_input = input("Enter an integer (or Q to quit): ").lower() 
    if "q" in user_input: 
        state= False
    else:
        combi.append(int(user_input))
else:
    final= sum([x+x for x in combi])
    print(final)