在字符串中添加函数

Question

我想使用time.sleep（）在字符串中添加特定的时间延迟，我正在构建一个文本交互游戏，我尝试了以下方法：

print(f"**inner thoughts** hmmmmm... {time.sleep(2)} maybe big nuke? {time.sleep(2)} or AK 47s for everyone? {time.sleep(2)} or kill him with our kindness? {time.sleep(2)} ")

问题是当我执行代码时，我得到的是（无）而不是时间延迟

inner thoughts hmmmmm... None maybe big nuke? None or AK 47s for everyone? None or kill him with our kindness? None

Answer 1

我提供了解决这个问题的模板方法

版本1，使用flag剪切文本（|对于此示例）：

text = "**inner thoughts** hmmmmm... | maybe big nuke? | or AK 47s for everyone? | or kill him with our kindness? |"
array = text.split("|")
for s in array:
    print(s, end="")
    time.sleep(1)

版本2：自定义延迟时间

import time
import re

text = "**inner thoughts** hmmmmm... {2} maybe big nuke? {2} or AK 47s for everyone? {1} or kill him with our kindness? {2}"
sub_text_array = re.split(r"{\d+}", text)
delay_array = [0] + [int(s) for s in re.findall(r"{(\d+)}", text)]
for index in range(len(sub_text_array)):
    time.sleep(delay_array[index])
    print(sub_text_array[index], end="")

Answer 2

f-串一次全部构建；您将看不到这种带有延迟的打印片段，因为当您sleep时字符串还没有结束，所以print甚至还没有被调用。如果您想这样做，您必须进行单独的print调用，中间有sleep；将其嵌入f字符串没有任何好处，您可能希望在等待之前执行类似操作以实际打印每个组件：

print("**inner thoughts** hmmmmm... ", end="", flush=True)
time.sleep(2)
print(" maybe big nuke? ", end="", flush=True)
time.sleep(2)
print(" or AK 47s for everyone? ", end="", flush=True)
time.sleep(2)
print(" or kill him with our kindness? ", end="", flush=True)
time.sleep(2)
print(" ")

end=""确保您不会移动到新行（遵循原始的一体式字符串格式），而flush=True确保数据不会在您睡觉时卡在缓冲区中等待（没有它，可能的行为是等待八秒钟，然后所有文本立即作为最后print的新行出现）导致行缓冲转储缓冲区）