列出每个获得奥斯卡奖的导演的获奖次数

Question

刚开始编程，试图找到解决方案，但一直没有找到正确的方法。试图为名单中的导演们列出奥斯卡获奖人数

**Input**
winners = {1931: ['Norman Taurog'], 1932: ['Frank Borzage'], 1933: ['Frank Lloyd'], 1934: ['Frank Capra'], 1935: ['John Ford'], 1936: ['Frank Capra'], 1937: ['Leo McCarey'], 1938: ['Frank Capra'], 1939: ['Victor Fleming'], 1940: ['John Ford'], 1941: ['John Ford'], 1942: ['William Wyler'], 1943: ['Michael Curtiz'], 1944: ['Leo McCarey'], 1945: ['Billy Wilder'], 1946: ['William Wyler'], 1947: ['Elia Kazan'], 1948: ['John Huston'], 1949: ['Joseph L. Mankiewicz'], 1950: ['Joseph L. Mankiewicz'], 1951: ['George Stevens'], 1952: ['John Ford'], 1953: ['Fred Zinnemann'], 1954: ['Elia Kazan'], 1955: ['Delbert Mann'], 1956: ['George Stevens'], 1957: ['David Lean'], 1958: ['Vincente Minnelli'], 1959: ['William Wyler'], 1960: ['Billy Wilder'], 1961: ['Jerome Robbins', 'Robert Wise'], 1962: ['David Lean'], 1963: ['Tony Richardson'], 1964: ['George Cukor'], 1965: ['Robert Wise'], 1966: ['Fred Zinnemann'], 1967: ['Mike Nichols'], 1968: ['Carol Reed'], 1969: ['John Schlesinger'], 1970: ['Franklin J. Schaffner'], 1971: ['William Friedkin'], 1972: ['Bob Fosse'], 1973: ['George Roy Hill'], 1974: ['Francis Ford Coppola'], 1975: ['Milos Forman'], 1976: ['John G. Avildsen'], 1977: ['Woody Allen'], 1978: ['Michael Cimino'], 1979: ['Robert Benton'], 1980: ['Robert Redford'], 1981: ['Warren Beatty'], 1982: ['Richard Attenborough'], 1983: ['James L. Brooks'], 1984: ['Milos Forman'], 1985: ['Sydney Pollack'], 1986: ['Oliver Stone'], 1987: ['Bernardo Bertolucci'], 1988: ['Barry Levinson'], 1989: ['Oliver Stone'], 1990: ['Kevin Costner'], 1991: ['Jonathan Demme'], 1992: ['Clint Eastwood'], 1993: ['Steven Spielberg'], 1994: ['Robert Zemeckis'], 1995: ['Mel Gibson'], 1996: ['Anthony Minghella'], 1997: ['James Cameron'], 1998: ['Steven Spielberg'], 1999: ['Sam Mendes'], 2000: ['Steven Soderbergh'], 2001: ['Ron Howard'], 2002: ['Roman Polanski'], 2003: ['Peter Jackson'], 2004: ['Clint Eastwood'], 2005: ['Ang Lee'], 2006: ['Martin Scorsese'], 2007: ['Ethan Coen', 'Joel Coen'], 2008: ['Danny Boyle'], 2009: ['Kathryn Bigelow'], 2010: ['Tom Hooper']}


best_director = []
for year, winnerlist in best_director:
    for winner in winnerlist:
        best_director[winner] = 1
    else:
        best_director[winner] += 1

print("Top winning director = {}".format(best_director))

**Output**
Top winning director = []

Answer 1

您需要反复浏览获奖者的项目：

for year, winnerlist in winners.items():

您还需要将best_director作为字典而不是列表。您还需要检查best_director中是否已经存在控制器，如果没有设置初始值，则增加计数。或者，您可以使用Counter

Answer 2

您可以使用collections.Counter和itertools.chain将所有名称组合在一起：

result = Counter(chain(*winners.values()))

---

Counter({'John Ford': 4, 'Frank Capra': 3, 'William Wyler': 3, 'Leo McCarey': 2, 'Billy Wilder': 2, 'Elia Kazan': 2, 'Joseph L. Mankiewicz': 2, 'George Stevens': 2, 'Fred Zinnemann': 2, 'David Lean': 2, 'Robert Wise': 2, 'Milos Forman': 2, 'Oliver Stone': 2, 'Clint Eastwood': 2, 'Steven Spielberg': 2, 'Norman Taurog': 1, 'Frank Borzage': 1, 'Frank Lloyd': 1, 'Victor Fleming': 1, 'Michael Curtiz': 1, 'John Huston': 1, 'Delbert Mann': 1, 'Vincente Minnelli': 1, 'Jerome Robbins': 1, 'Tony Richardson': 1, 'George Cukor': 1, 'Mike Nichols': 1, 'Carol Reed': 1, 'John Schlesinger': 1, 'Franklin J. Schaffner': 1, 'William Friedkin': 1, 'Bob Fosse': 1, 'George Roy Hill': 1, 'Francis Ford Coppola': 1, 'John G. Avildsen': 1, 'Woody Allen': 1, 'Michael Cimino': 1, 'Robert Benton': 1, 'Robert Redford': 1, 'Warren Beatty': 1, 'Richard Attenborough': 1, 'James L. Brooks': 1, 'Sydney Pollack': 1, 'Bernardo Bertolucci': 1, 'Barry Levinson': 1, 'Kevin Costner': 1, 'Jonathan Demme': 1, 'Robert Zemeckis': 1, 'Mel Gibson': 1, 'Anthony Minghella': 1, 'James Cameron': 1, 'Sam Mendes': 1, 'Steven Soderbergh': 1, 'Ron Howard': 1, 'Roman Polanski': 1, 'Peter Jackson': 1, 'Ang Lee': 1, 'Martin Scorsese': 1, 'Ethan Coen': 1, 'Joel Coen': 1, 'Danny Boyle': 1, 'Kathryn Bigelow': 1, 'Tom Hooper': 1})

要获得“最佳”导演，只需使用Counter.most_common：

result.most_common(1)[0][0]

---

John Ford

编辑：如果您只需要最常用的名称，也可以使用statistics.mode和itertools.chain：

mode(chain(*winners.values()))

---

John Ford

Answer 3

试试get：

best_director = {}
for year, winnerlist in winners.items():
    for winner in winnerlist:
        best_director[winner] = best_director.get(winner, 0) + 1

print("Top winning director = {}".format(max(best_director, key=lambda x: best_director[x])))