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Question

我正在从以前请求的url获取数据。到目前为止一切正常

我的问题是： 我尝试每X秒进行一次查询，如果查询显示不同的值，则应该执行一些操作。但即使在最终响应返回时也会打印解决捕获！=未准备好

 responseback = requests.get('https://2captcha.com/res.php?json=1&action=get&key=' + apikey + "&id=" + finalrequest)

 responseback_json = responseback.json()
 finalresponseback = responseback_json['request']
 print(responseback_json)
 notready = (str("CAPCHA_NOT_READY"))



 while(finalresponseback == notready):
     print("Solving-Capture...")
     if finalresponseback != notready:
         print("Entering...")

Answer 1

这是因为你写代码的方式， 假设最终回复尚未准备就绪，则会发生以下情况：

while(finalresponseback == notready): # This would enable the loop because it's equal to not ready
    print("Solving-Capture...") # It would print this
    if finalresponseback != notready: # Nothing would happen because it is equal to notready
        print("Entering...") # This woudln't happen

但是，如果突然发生变化：

while(finalresponseback == notready): # This happened before it changed
    print("Solving-Capture...") # This also happened before it changed, so it happens anyway
    if finalresponseback != notready: # This happens too
        print("Entering...") # And so does this, so therefore it would print both statements

此代码不好，因为如果它更改为not be notready（未准备就绪），则它将退出循环而不执行任何操作，除非它在循环中更改，否则更好的版本是：

while(1): # Starts a loop
    if finalresponseback != notready: # Checks finalresponseback
        print("Entering...") # Prints statement
        break # Exits loop
    else: # If it is equal to notready
        print("Solving-Capture...") # Print statement

上面的代码直接检查循环中的finalresponseback，因此，它将能够打印语句，而不是像以前一样在开始时完全退出

最后，我们可以添加：

responseback_json = responseback.json()
finalresponseback = responseback_json['request']

每x秒请求一次的代码，如下所示：

import time # Add to top of code, imports the time library
x = 2 # Sets the x variable
while(1): # Starts a loop
    responseback_json = responseback.json()
    finalresponseback = responseback_json['request']
    if finalresponseback != notready: # Checks finalresponseback
        print("Entering...") # Prints statement
        break # Exits loop
    else: # If it is equal to notready
        print("Solving-Capture...") # Print statement
    time.sleep(x)

最后，是优化代码的技巧，而不是

notready = (str("CAPCHA_NOT_READY"))

你能行

notready = "CAPCHA_NOT_READY"

这是因为它已经是一个字符串值（由语音标记“”指示）